Quantum physics basics: photoelectric effect, de Broglie waves
Engineering Physics · Engineering
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Study notes
Light of λ = 400 nm hits a metal with work function φ = 2.0 eV. Find max KE of emitted electrons. Photon energy: E = hc/λ = 1240/400 = 3.1 eV. KE_max = 3.1 − 2.0 = 1.1 eV. In joules: 1.1 × 1.6×10⁻¹⁹ = 1.76×10⁻¹⁹ J.
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