Applications to diet, manufacturing and transport
General · Mathematics
Study notes
Q: Diet: food A ₹10 (protein 5, iron 2), B ₹15 (protein 3, iron 4). Need protein ≥ 30, iron ≥ 20. Formulate. Min Z = 10x+15y. 5x+3y ≥ 30 (protein!), 2x+4y ≥ 20 (iron!), x,y ≥ 0. (≥ constraints: feasible region above lines!) Corner method finds cheapest mix!