Approximations using differentials
Differentiation · Mathematics
Study notes
Q: Approximate sqrt(26) using differentials with x=25. f(x)=sqrt(x), f'(x)=1/(2sqrt(x)). dx=1. dy = 1/(2*5)*1 = 0.1. sqrt(26) approx 5 + 0.1 = 5.1. (True: 5.099 - excellent!)