Frustum of a cone
Mensuration · Mathematics
Study notes
Q: Bucket: R = 10, r = 6, h = 12. Volume? Slant height? l = √(144+16) = √160 = 4√10 ≈ 12.65. V = π×12×(100+60+36)/3 = 4π×196 = 784π ≈ 2463. CSA: π(10+6)×12.65 ≈ 635.5! (Frustum: big cone minus small cone!)