Limits of functions (rigorous epsilon-delta)
General · Mathematics
Study notes
Q: Prove lim(x→3) 2x = 6 using ε-δ. Need: |2x-6| < ε when |x-3| < δ. |2x-6| = 2|x-3| < 2δ. Set 2δ = ε: δ = ε/2. Given ε > 0, δ = ε/2: |x-3| < δ → |2x-6| < ε ✓! (QED - the game: ε given, find δ!)