Locus and its equation
Two-dimensional geometry · Mathematics
Study notes
Q: Find the locus of P(x,y) such that PA = PB where A = (2,0), B = (−2,0). √[(x−2)²+y²] = √[(x+2)²+y²] Square: (x−2)² = (x+2)² → −4x = 4x → x = 0. Locus: the y-axis (perpendicular bisector!).