Applications of dimensional analysis
Dimensions and dimensional analysis · Physics
Study notes
Derive the period of a simple pendulum (depends on l, g). Assume T ∝ l^a g^b → [T] = [L]^a [LT⁻²]^b [T¹] = [L^(a+b) T^(-2b)] Matching: a+b=0, -2b=1 → b=-½, a=½ T ∝ √(l/g). True formula: T = 2π√(l/g) ✓